Convert Decimal to Binary in C#

In this article I will explain how you will convert decimal number to binary in c#. So let's first we need understand what is decimal and what is binary number.

Decimal Number

Decimal number is a base 10 number because it ranges from 0 to 9, there are total 10 digits between 0 to 9. Any combination of digits is decimal number such as 223, 585, 192, 0, 7 etc.

Binary Number

Binary number is a base 2 number because it is either 0 or 1. Any combination of 0 and 1 is binary number such as 1001, 101, 11111, 101010 etc.

Before starting the Example Please remember the algorithm for the conversion.

  • Divide the number by 2 through % (modulus operator) and store the remainder in array
  • Divide the number by 2 through / (division operator)
  • Repeat the step 2 until the number is greater than zero

Let's take an Example to see how to convert Decimal number to Binary in C#.
    using System;  
      public class DecimalToBinary
       {  
         public static void Main(string[] args)  
          {  
           int  n, i;       
           int[] a = new int[10];     
           Console.Write("Enter the number to convert: ");    
           n= int.Parse(Console.ReadLine());     
           for(i=0; n>0; i++)      
            {      
             a[i]=n%2;      
             n= n/2;    
            }      
           Console.Write("Binary of the given number= ");      
           for(i=i-1 ;i>=0 ;i--)      
           {      
            Console.Write(a[i]);      
           }                 
          }  
      }  
Output:
Enter the number to convert:10
Binary of the given number= 1010 

Program Explanation
This C# program, we are declaring the variable ‘n’ and ‘i’ Integer type. Using for loop check the value of ‘n’ variable is greater than 0 and also greater than 1.
The variable bin will get the value of the operation, the variable n value % 2; the Mod is used to obtain a division residue. Divide the numbers to indicate next to the symbol %, this case the number 2, because 2 is the binary numbers base. Then after obtaining the first residue the variable ‘n’ will get its own value between 2.



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